Question

A spanner of length 10 cm is used to open a nut by applying a minimum force of 5.0 N. Calculate the moment of force required.

A. 5 N cm
B. 5 N m
C. 500 N cm

Answer 1

⊥ Distance = 10cm=10/100=1/10m
Force applied on spanner 5N
∴ Moment of force = F×⊥ distance.
=5×1/10=0.5mm
Please mark as Brainliest

Answer 2

Answer:-

$\color{purple} \sf= 1/10 \: m \: force \: applied \: on$

$\color{purple} \sf\:spanner \: 5 \: n$

$\color{orange} \sf \: ∴ moment \: of \: force$

$\color{orange} \sf = f \times ⊥ = 5 \times 1/10 = 0.5 \: nm$