Question

A spanner of length 10 cm is used to unscrew a nut by applying a minimum force of 5.0 N. Calculate the moment of force required.
​

Answer 1

Convert 10 cm to m

=> 10/100 m = 0.01 m

=> Torque = Force x length of spanner

=> Torque = (5 x 0.01) N-m

=> Torque = 0.05 N-m

Answer 2

  ⊥ Distance = 10cm = 10/100 = 1/10 m Force applied on spanner 5 N ∴ Moment of force = F ×⊥ distance = 5 × 1/10 = 0.5 nm