A spanner of length 10cm is used to open a nut by applying a minimum force of 5.0N . calculate the moment of force required
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Answered by
92
Moment of force =force ×perpendicular distance
=5×10
=50NCm
=5×10
=50NCm
Answered by
13
Given,
Length of the spanner=10cm
Minimum force=5N
To Find,
Moment of force.
Solution,
We know moment of force is calculated by minimum force applied on the object and the perpendicular distance from the centre on it.
So, Moment of force =applied force ×perpendicular distance
=5N×0.1m(10cm=10/100m=0.1m)
=0.5Nm
Hence, the moment of force is 0.5Nm.
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