Question

A
spanner of length  30 cm is used to open a nut by applying a minimum force of  6.0 N. Calculate the moment of force required.

Answer 1

2 pa is the correct answer

Answer 2

Answer:

• 1.8 Nm.

Explanation:

Given: Perpendicular distance (d) = 30cm

=> 30 cm = 30/100m = 0.3m

& Force applied (F) = 6N

To find: Moment of force (M)

Solution: Moment of force = Force × Perpendicular distance

=> M = 6 × 0.3

∴ M = 1.8 Nm

Hence, the moment of force required to 1.8 Nm.