A speaks truth 4 out of 5 times. A die is tossed. He reports that there is a six. What is the chance that actually there was six?
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Answered by
8
Answer:
Step-by-step explanation:
Hope this helps you
A man speaks truth 4 out of 5 times. Probability of speaking truth will be 4/5. He reports that there is a six. So probability of event occurring 1/6.
Given they are not mutually exclusive. Probability of actual six,
1/4 * 4/5 = 5/12 ~ 0.4166
Therefore, probability that it was actual six is 0.4166.
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Answered by
1
Answer:
Step-by-step explanation:
It consists of two cases mainly. They are 1. It is a six and he has said the truth =(1/6)*(4/5) =x
2. It is not a 6 and he has lied =(5/6)*(1/5)=y
So the answer will be x/x+y
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