Question

A speaks truth 4 out of 5 times.a die tossed.he reports that there is a six.what is the probability that it was actually a six?

Answer 1

Answer:

p(E) =4/5

P(E')=1/5

P(A)=1/6

P(A')=5/6

If P(E1) is the probability of that the speaks tell truth and it is really 6 Then

PE/E1) = P(E)× P(A)/ P(E)×P(A)+P(E')×P(A')

=4/5×1/6 / 4/5×1/6+1/5×5/6

=4/9

Step-by-step explanation: