A speaks truth 70% of the time; b speaks truth 80% of the time. What is the probability that both are contradicting each other?
Answers
Answered by
0
a
A speaks 70% And B speaks 80%
the probability of A is less than 100%
the p [B] = 80%/100%
and the p[A]=70/100
A speaks 70% And B speaks 80%
the probability of A is less than 100%
the p [B] = 80%/100%
and the p[A]=70/100
Similar questions