A speaks truth in 25% of cases and B in 20% of cases. In what percentage of cases are they likely to agree with each other, narrating the same incident?
Select one:
a. 60%
b. 65%
c. 45%
d. 5%
Answers
Answered by
44
- ➡️Let A = Event that A speaks the truth B = Event that B speaks the truth
- B = Event that B speaks the truthThen P(A) = 25/100 = 1/4 P(B) = 20/100 = 1/5
- P(B) = 20/100 = 1/5P(A-lie) = 1-1/4 = 1/4 . P(B-lie) = 1-1/5 = 1/5
- P(B-lie) = 1-1/5 = 1/5Now
A and B contradict each other =
[A lies and B true] or [B true and B lies]
= P(A).P(B-lie) + P(A-lie).P(B)
[Please note that we are adding at the. place of OR]
= (3/5*1/5) + (1/4*4/5) = 7/20
= (7/20 * 100) % = 35%
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Answered by
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Answer:
Answer
➡️Let A = Event that A speaks the truth B = Event that B speaks the truth
B = Event that B speaks the truthThen P(A) = 25/100 = 1/4 P(B) = 20/100 = 1/5
P(B) = 20/100 = 1/5P(A-lie) = 1-1/4 = 1/4 . P(B-lie) = 1-1/5 = 1/5
P(B-lie) = 1-1/5 = 1/5Now
A and B contradict each other =
[A lies and B true] or [B true and B lies]
= P(A).P(B-lie) + P(A-lie).P(B)
[Please note that we are adding at the. place of OR]
= (3/5*1/5) + (1/4*4/5) = 7/20
= (7/20 * 100) % = 35%
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