Math, asked by nidhipoppins5889, 1 year ago

A speaks truth in 60% and in 80% of the cases. In what percentage of cases are they likely to contradict each other narrating the same incident?

Answers

Answered by aadithyakurup2005
1

Answer:

Step-by-step explanation:

The situation is probably best represented by the following table (there are two options for both A and B, thus giving four distinct outcomes):

A speak truth - 0.60 * 0.80 = 0.48 (or 48%)

A speaks the truth, B lies - 0.60 * (1–0.8) = 0.12 (or 12%)

A lies, A speaks the truth - (1–0.60) * 0.8 =0.32  (or 32%)

A  lie - (1–0.60) * (1–0.8) = 0.08 (or 8%)

What is not entirely clear from the question is whether both A and B will lie in the same way - depending on that, the answer is either 35% (adding options 2 and 3) or 40% (adding options 2, 3, and 4).

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