Question

A speaks truth in 60% of cases and b in 70% of cases in what % cases are they likely to contradict each other in stating the same fact?

Answer 1

10% - 70% is the answer

Answer 2

Answer: 46%

Step-by-step explanation:

probability that A speak truth p(A)= 60% or 0.60

probability that B speak truth P(B)= 70% or 0.70

probability that A speak lie P(A')= 1-p(A) =0.40

probability that B speak lie P(B')= 0.30

probability that contradict of A and B = p(A and B') or P(A' and B)

= p(A)*p(B)+P(A')*P(B)

= 0.60*0.30+0.40*0.70

= 0.46

Required percentage = 0.46*100 = 46%