A speaks truth in 60% of cases and b in 70% of cases in what % cases are they likely to contradict each other in stating the same fact?
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10% - 70% is the answer
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Answer: 46%
Step-by-step explanation:
probability that A speak truth p(A)= 60% or 0.60
probability that B speak truth P(B)= 70% or 0.70
probability that A speak lie P(A')= 1-p(A) =0.40
probability that B speak lie P(B')= 0.30
probability that contradict of A and B = p(A and B') or P(A' and B)
= p(A)*p(B)+P(A')*P(B)
= 0.60*0.30+0.40*0.70
= 0.46
Required percentage = 0.46*100 = 46%
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