Biology, asked by sticks, 18 days ago

A species of buttercup (A) is thought to be able to accumulate nickel in its tissues. A comparable species (B) is not an accumulator.

Species A therefore may be useful for removing nickel pollution from the soil.

Each species of buttercup were seeded into two separate plots, one of which had previously been treated with 3g of nickel sulphate per square meter. Watering and other variables were controlled in all the plots.

A month after germination, the populations were counted using quadrats of 1m2 and the following results were obtained:

Species

Untreated plot

Treated plot

A

486 plants in 6 quadrats

608 plants in 8 quadrats

B

584 plants in 8 quadrats

115 plants in 5 quadrats



Calculate comparable results and a suitable unit for the plant population in the two plots (2 marks)
Species

Density of plants in the Untreated plot. Plants/m2

Density of plants in the treated plot.
Plants/m2

A





B





Suggest a hypothesis to explain the difference in populations of the two species in the treated and untreated plots.(2 marks)
Complete the table for each plant and perform the X2 test to test whether there is a significant difference in the populations of species A in the two plots measured, one untreated and one treated with Nickel sulphate. (5 marks)

Answers

Answered by naman195287
0

Answer:

A species of buttercup (A) is thought to be able to accumulate nickel in its tissues. A comparable species (B) is not an accumulator.

Species A therefore may be useful for removing nickel pollution from the soil.

Each species of buttercup were seeded into two separate plots, one of which had previously been treated with 3g of nickel sulphate per square meter. Watering and other variables were controlled in all the plots.

A month after germination, the populations were counted using quadrats of 1m2 and the following results were obtained:

Species

Untreated plot

Treated plot

A

486 plants in 6 quadrats

608 plants in 8 quadrats

B

584 plants in 8 quadrats

115 plants in 5 quadrats

Calculate comparable results and a suitable unit for the plant population in the two plots (2 marks)

Species

Density of plants in the Untreated plot. Plants/m2

Density of plants in the treated plot.

Plants/m2

A

B

Suggest a hypothesis to explain the difference in populations of the two species in the treated and untreated plots.(2 marks)

Complete the table for each plant and perform the X2 test to test whether there is a significant difference in the populations of species A in the two plots measured, one untreated and one treated with Nickel sulphate. (5 marks)

Answered by x229
0

Answer:

Explanation:

not sure

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