Question

A species of shark has the length of their teeth controlled by a gene ‘T’ where long is dominant to short. A homozygous long toothed shark (TT) and a heterozygous long toothed shark (Tt) have an allele frequency of T: 0.75, t: 0.25. If they have 10 offspring and 6 are homozygous long toothed sharks and 4 are heterozygous long toothed sharks, what is the new allele frequency?

Answer 1

Answer:

New allele is the Heterozygous one which is different from parents.

So, their frequency = 2Tt = 2×0.75×0.25 = 0.375

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