Question

a speed boat increase its speed uniformly from 20m/s to 30m/s in a distance of 200m.find a the magnitude of its acceleration b)the time it take the the boat to travel the 200m distance

Answer 1

hi friend,

given u=20m/
v=30m/s

s=200m


we know that v²-u²=2as

900-400=400a

500=400a

a=1.25m/s²


we also know that


v=u+at

30=20+1.25t

10/1.25=t

t=8s


I hope this will help u ;)

Answer 2

Answer:

The magnitude of its acceleration a = 1.25$m/s^{2}$

The boat takes 8s to travel 200m.

Explanation:

From the given take the initial velocity (u)=20$\frac{m}{s}$

the Final velocity (v)=30$\frac{m}{s}$

the Distance (s) =200 m

we know that the formula for the magnitude of its acceleration

$v^{2} -u^{2} =2as$

900-400=400a

500=400a

= 1.25$m/s^{2}$

Therefore, The magnitude of acceleration a = 1.25$m/s^{2}$

we also know that the formula to find time to travel the distance

v=u+at

As we derived a = 1.25$m/s^{2}$, substitute it in the formula.

30=20+1.25t

$\frac{10}{1.25}$ = t

Time (t) = 8s

Therefore the boat takes 8s to travel a 200m distance.

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