Question

a speed of 90 km/h. The brakes are applied so as to produce a uniform
7. A train is travelling at a speed of 90 km/h. The brakes are applied so a
acceleration of -0.5m/s. Find how far the train goes before it stops?​

Answer 1

Explanation:

U:90km/hr=90*5\18=25m/s

A:-0.5m/sec

t:?

S:?

Answer 2

Answer:

625 m

Explanation:

u= 90 kmph

 =25 m/s

v=0

a= -0.5 m/s²

using third equation of motion,

v²-u²=2aS

-625=2×-0.5×S

-625=-1S

minus symbol gets cancelled on both sides leaving,

S= 625 m

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