Question

a speed of an airplane is 885 km per hour.find the distance covered by the airplane in 3 hours and 20 minutes also, express the distance in scientific notation.​

Answer 1

Step-by-step explanation:

in order to find the plane's speed over 3 hours you simply multiply the speed by 3:

885*3 = 2,655

to find the extra 20 minutes you need to figure out what part of an hour 20 minutes are, which is done by:

20:60 = 0.33 = $\frac{1}{3}$

so then you multiply $\frac{1}{3}$ * 885 = 295

than you just add them together:

295 + 2,655 = 2,950

in mathematical notation the answer would be 2.95 × $10^{3}$

Answer 2

$\sf\huge\bold{Answer:}$

Given :

• speed of an airplane = 885 km/h
• Time=3hrs20min

To find :

• Distance covered by plane

Solution :

$\fbox{Formula used :}$

$\tt\red{ :⟶distance = speed \times time}$

Speed=885km/h

Time=3hr+20min

[1min=1/60hr]

=3hr+(20/60)hr

=3hr+⅓hr

=3⅓hr

• Inserting values in formula :

$\tt\ :⟶d = \big(885 \times 3 \frac{1}{3} \big)km$

• Converting mixed fraction into improper fraction

$\tt\ :⟶d = 885 \times \frac{3 \times 3 + 1}{3} \: \: \: km$

$\tt\ :⟶d = \big(885 \times \frac{10}{3} \big)km$

$\tt\ :⟶d = \big( \frac{8850}{3} \big)km$

$\tt\ :⟶d = 2950km$

$\tt\red{ 1km = 0.001m}$

$\tt\ :⟶d = 2.950m$

Distance covered by plane is 2950km or 2.95 m

• Converting distance in scientific notation

$\tt\ :⟶d = 2950 \times \frac{1000}{1000} \\ \:$

$\tt:⟶d=2.95 \times 10 {}^{3}$

$\tt\purple{d=2.95 \times 10 {}^{3} }$

Distance covered by plane is 2.95×10³ km