A speed- time graph for a body thrown vertically upwards and then caught at the
same place
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Velocity will first decrease according to the equation v=u−gt where u is initial velocity(at t=0 ) so the graph can't start from origin because u is not zero as thrown with some velocity and v is final velocity. then t=u/g the v will become zero then it will start increasing in opposite direction , if the upward direction is taken as positive then the downward velocity will be negative.
Option A is correct as after certain point velocity becomes negative and get increasing.
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