Physics, asked by nilakshi89, 7 months ago

A speeding boat in water experiences an acceleration of 0.524 m/s^2.The boat's mass is 842 kg. what is the force that engines are pulling out ?​

Answers

Answered by BrainlyIAS
55

\huge\ \; \bigstar\ \;  \sf \orange{F=ma}

where ,

  • F denotes force
  • m denotes mass
  • a denotes acceleration

Given :

  • a = 0.524 m/s²
  • m = 842 kg

\to \sf F=ma\\\\\to \sf F=(842)(0.524)\\\\\to \sf F=441.208\\\\\to \sf F\cong 441.2\ N\ \; \bigstar

So , the force with which the engine pulling out is 441.2 N

More Info :

Equations of motion :

→  v = u + at

→  s = ut + ¹/₂ at²

→  v² - u² = 2as

Answered by Rudranil420
34

Answer:

Given

A speeding boat in water experiences an acceleration of 0.524 m/.

The boat's mass is 842 kg.

To Find

What is the force of that engines are pulling out.

Formula Used

F = ma ✳

Solution

Given:-

  • Acceleration (a) = 0.524 m/
  • Mass (m) = 842 kg

According to the question,

\implies F = (842)(0.524)

\implies F = 441.208

\implies F = 441.2 N

Hence, the force that engines are pulling is 441.2 N .

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