A speeding boat in water experiences an acceleration of 0.524 m/s^2.The boat's mass is 842 kg. what is the force that engines are pulling out ?
Answers
Answer:
★ F=ma
where ,
F denotes force
m denotes mass
a denotes acceleration
Given :
a = 0.524 m/s²
m = 842 kg
\begin{gathered}\to \sf F=ma\\\\\to \sf F=(842)(0.524)\\\\\to \sf F=441.208\\\\\to \sf F\cong 441.2\ N\ \; \bigstar\end{gathered}
→F=ma
→F=(842)(0.524)
→F=441.208
→F≅441.2 N ★
So , the force with which the engine pulling out is 441.2 N
More Info :
Equations of motion :
→ v = u + at
→ s = ut + ¹/₂ at²
→ v² - u² = 2as
Answer:
here is your answer
step by step explanation
Given ✡
✏ A speeding boat in water experiences an acceleration of 0.524 m/s².
✏ The boat's mass is 842 kg.
✡ To Find ✡
✏ What is the force of that engines are pulling out.
✡ Formula Used ✡
✳ \bold{\huge{\fbox{\color{blue} {F = ma }}}}
F = ma
✳
✡ Solution ✡
Given:-
Acceleration (a) = 0.524 m/s²
Mass (m) = 842 kg
▶ According to the question,
\implies⟹ F = (842)(0.524)
\implies⟹ F = 441.208
\implies⟹ F = \text{\large\underline{\pink{441.2 N}}}
441.2 N
Hence, the force that engines are pulling is 441.2 N