Question

A speeding car changes its velocity from 108km/h to 36km/h. Calculate its deceleration in 1) m/s^2 2)Km/h^2

Answer 1

Answer:

Assuming you are asking constant deceleration.

(I) u = 108x5/18 m/s = 30 m/s

v = 36x5/18 m/s = 10m/s

t = 4 sec

a = (v-u)/t = (10 - 30) /4 = -5m/s²

*Deceleration = 5 m/s²*

(II) t = 4/3600 hr

a = (v-u)/t

(36-108)/(4/3600) = -64800km/hr²

*Deceleration = 64800 km/hr²*

Explanation:

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