Question

A speeding motorcyclist sees traffic jam ahead of him. He slows down to 36 km/hour. He finds that traffic has eased and a car moving ahead of him at 18 km/hour is honking at a frequency of 1392 hz. If the speed of sound is 343 m/s, the frequency of the honk as heard by him will be :

Answer 1

Answer:

1412Hz

Step-by-step explanation:

$v'=v(\frac{v+v_{c} }{v+v_{m} } )$

here $v_{c} =velocity of car &\\v_{m} = velocity of motorcycle$

$v_{c}  = 18*\frac{5}{18}  = 5 ms^{-1}$

$v_{m}  = 36 * \frac{5}{18}  = 10ms^{-1}$

$v' =1392 (\frac{343+10}{343+5} )$

$1392(\frac{353}{348} )$

v' = 1412 Hz

Answer 2

Answer:1412

Step-by-step explanation: