A sphere a cyliender and a cone have same diameter.the height of the cylinder and also the cone are equal to the diameter of sphere find the ratio of their volume
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Answered by
13
Let the diameter of sphere, cylinder and cone be 2r
Then their radius will be r
and height of cylinder and cone will be 2r
Hence required ratio = Volume of sphere : Volume of cylinder : Volume of cone
= 4πr3 : 6πr3 : 2πr3
= 2 : 3 : 1
=4/3πr*3:πr*2×2r:1/3πr*2×2r
Answered by
34
️Since we know that,
Volume of sphere = 4/3 πr³
Volume of cylinder = πr²h
Volume of cone = 1/3 πr²h
➣ Let the radius of sphere be x
➣ Then diameter of sphere = 2x
Since diameter of sphere = height of cylinder and cone.
➣ So, height of cylinder = that of cone = 2x
✍ If sphere, cylinder and cone have same diameter then they will also have same radius of base.
So, volume of sphere = 4/3 πr³
= 4/3 π(x)³ = 4/3 πx³
Volume of cylinder = πr²h
= πx² × 2x = 2πx³
Volume of cone = 1/3 πr²h
= 2/3 πx³
➣ So, volume of sphere / cylinder / cone
= ( 4/3 πx³ ) : ( 2πx³ ) : ( 2/3 πx³ )
= ( 4/3 ) : ( 2 ) : ( 2/3 )
➣ LCM of their denominators we get,
= ( 4/3 × 3 ) : ( 2 × 3 ) : ( 2/3 × 3 )
= 4 : 6 : 2
✪ Answer⇒ 4 : 6 : 2
Volume of sphere = 4/3 πr³
Volume of cylinder = πr²h
Volume of cone = 1/3 πr²h
➣ Let the radius of sphere be x
➣ Then diameter of sphere = 2x
Since diameter of sphere = height of cylinder and cone.
➣ So, height of cylinder = that of cone = 2x
✍ If sphere, cylinder and cone have same diameter then they will also have same radius of base.
So, volume of sphere = 4/3 πr³
= 4/3 π(x)³ = 4/3 πx³
Volume of cylinder = πr²h
= πx² × 2x = 2πx³
Volume of cone = 1/3 πr²h
= 2/3 πx³
➣ So, volume of sphere / cylinder / cone
= ( 4/3 πx³ ) : ( 2πx³ ) : ( 2/3 πx³ )
= ( 4/3 ) : ( 2 ) : ( 2/3 )
➣ LCM of their denominators we get,
= ( 4/3 × 3 ) : ( 2 × 3 ) : ( 2/3 × 3 )
= 4 : 6 : 2
✪ Answer⇒ 4 : 6 : 2
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