A sphere,a cylinder and a cone are of the same radius and same height .find the ratio of their curved surface areas?
Answers
Answered by
17
The standard formulae for respective curved areas are
Surface area of sphere 4πr^2
Area of lateral surface of cylinder 2πrh
Area of lateral surface of cone πr√(r^2 + h^2)
The height of a sphere is the diameter 2r. Since the cylinder and
cone are specified as the same height we substitute h = 2r
Specific formulae are now
Surface area of sphere 4πr^2
Area of curved surface of cylinder 2πr*2r = 4πr^2
Area of curved surface of cone πr√(r^2 + 4r^2) = πr^2√(5)
Dividing by 4πr^2 yields the ratio of their curved surfaces as
1: 1: √(5)/4
Surface area of sphere 4πr^2
Area of lateral surface of cylinder 2πrh
Area of lateral surface of cone πr√(r^2 + h^2)
The height of a sphere is the diameter 2r. Since the cylinder and
cone are specified as the same height we substitute h = 2r
Specific formulae are now
Surface area of sphere 4πr^2
Area of curved surface of cylinder 2πr*2r = 4πr^2
Area of curved surface of cone πr√(r^2 + 4r^2) = πr^2√(5)
Dividing by 4πr^2 yields the ratio of their curved surfaces as
1: 1: √(5)/4
Answered by
0
Answer:
1:1:√[5]/4
Step-by-step explanation:
The standard formulae for respective curved areas are
Surface area of sphere 4πr^2
Area of lateral surface of cylinder 2πrh
Area of lateral surface of cone πr√(r^2 + h^2)
The height of a sphere is the diameter 2r. Since the cylinder and
cone are specified as the same height we substitute h = 2r
Specific formulae are now
Surface area of sphere 4πr^2
Area of curved surface of cylinder 2πr*2r = 4πr^2
Area of curved surface of cone πr√(r^2 + 4r^2) = πr^2√(5)
Dividing by 4πr^2 yields the ratio of their curved surfaces as
1: 1: √(5)/4
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