A sphere and a right circular cylinder of a same radius have equal volumes. by what percent does the diameter of the cylinder exceeds its height.
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According to question:
Let radius of sphere = radius of right circular cylinder =R
volume of cylinder = πR²h
volume of sphere = 4/3πR³
According to question:
4/3πR³ = πR²h
R = ¾h ----->(1.)
then,
Diameter = 2*¾h => 3/2*h
Percentage required:
[(3/2*h) / (h)] * 100 = 150%
Let radius of sphere = radius of right circular cylinder =R
volume of cylinder = πR²h
volume of sphere = 4/3πR³
According to question:
4/3πR³ = πR²h
R = ¾h ----->(1.)
then,
Diameter = 2*¾h => 3/2*h
Percentage required:
[(3/2*h) / (h)] * 100 = 150%
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