Question

a sphere has a hollow portion which is one third of its total volume it floats in water with four fifth of its volume immersed the specific gravity of its material is​

Answer 1

The specific gravity of the material is 2.67

Explanation:

Density of body = fraction of body in liquid x density of water

=( 1 — 1/3) x 1 = 2/3

Density of liquid = density of body / fraction of body in liquid

= 2 / 3 ÷ 1 / 4

= 2 x 4 / 3 x 1

= 8 / 3

= 2.67

Thus the specific gravity of the material is 2.67

Answer 2

The correct answer is 0.833.

Given: One third of its total volume it floats in water.

four fifth of its volume immersed in water.

To Find: The specific gravity of material.

Solution:

Density of body = fraction of body in liquid x density of water

= ( 1 — $\frac{1}{3}$) x 1 = $\frac{2}{3}$

Density of liquid = density of body / fraction of body in liquid

= $\frac{\frac{2}{3} }{\frac{4}{5} }$

= $\frac{2}{3}*\frac{5}{4}$

= $\frac{5}{6}$

= 0.833

Hence,  the specific gravity of the material is 0.833.

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