Question

A sphere is attached to an inextensible string of length 0.5 m whose upper end is fixed to ceiling. The sphere has mass of 0.2 kg and is made to describe horizontal circle of radius 0.3 m. The speed of sphere is​

Answer 1

Explanation:

m=200g

l=130cm

130cm=1.3 metre

So the time period of a pendulum doesn't depend on the mass of the Bob. It is equal to :

g

2π

l

(2pi×rootl/rootg) where l is length and g is gravity. Which gives us:

t2=4π2×1.3/9.8 (squaring both sides)

π2 and 9.8 are approx the same so we can cut it out, giving us:

4×1.3=520s

Therefore t2=5.2

t=2.29s

As per the second part of the question, the force on the string is simple mg = 200×10=2000 gram m/s^2

Or 200gf

Or 0.2kg×10=2N

thank you

please mark me as brainlist

Answer 2

Answer:

Your answer is 1.5 m/s

Explanation:

tan o = v^2/rg

v^2 = rg tano

      = 0.3 * 10 * 3/4

      = 2.25

So v = 13.5 m/s

Mark me as brainliest