a sphere is charged to 20 micro coulomb find the potential at the following point ( at A at B at C ) a point is at the centre of the sphere , B is at the surface and c is 4cm from the surface.
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Answer:
this is answer
Explanation:
V_A=\frac{(9\cdot10^{9})(20\cdot10^{-6})}{0.02}=9\cdot10^{6}V\\V_B=\frac{(9\cdot10^{9})(20\cdot10^{-6})}{0.02}=9\cdot10^{6}V\\V_C=\frac{(9\cdot10^{9})(20\cdot10^{-6})}{0.02+0.04}=3\cdot10^{6}VV
A
=
0.02
(9⋅10
9
)(20⋅10
−6
)
=9⋅10
6
V
V
B
=
0.02
(9⋅10
9
)(20⋅10
−6
)
=9⋅10
6
V
V
C
=
0.02+0.04
(9⋅10
9
)(20⋅10
−6
)
=3⋅10
6
V
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