Question

a sphere is charged to 20 micro coulomb find the potential at the following point ( at A at B at C ) a point is at the centre of the sphere , B is at the surface and c is 4cm from the surface.

Answer 1

Answer:

this is answer

Explanation:

V_A=\frac{(9\cdot10^{9})(20\cdot10^{-6})}{0.02}=9\cdot10^{6}V\\V_B=\frac{(9\cdot10^{9})(20\cdot10^{-6})}{0.02}=9\cdot10^{6}V\\V_C=\frac{(9\cdot10^{9})(20\cdot10^{-6})}{0.02+0.04}=3\cdot10^{6}VV  

A

​  

=  

0.02

(9⋅10  

9

)(20⋅10  

−6

)

​  

=9⋅10  

6

V

V  

B

​  

=  

0.02

(9⋅10  

9

)(20⋅10  

−6

)

​  

=9⋅10  

6

V

V  

C

​  

=  

0.02+0.04

(9⋅10  

9

)(20⋅10  

−6

)

​  

=3⋅10  

6

V