A sphere is placed in an inverted hollow conical vessel of base radius 5cm and the vertical height 12cm. If the highest point of the sphere is at the level of the base of the cone. Find the radius of sphere.show that the volume of sphere and the conical vessel are as 40:81
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Sol: Let the radius of the sphere = r cm. OD = OE = r Height of the cone EA = 12 cm Slant height AC = √{ 52 + 122 } = √169 = 13 cm. In ΔAEC and ODA we have ∠AEC = ∠ODA = 90° ⇒ ΔAEC ≃ ODA [ AA similarity ] ⇒ OD / OA = EC / AC ⇒ r / ( 12 - r) = 5 / 13 ⇒ r = 10 / 3 cm ∴ Volume of the sphere / Volume of the cone = ( 4/3)πr3 / (1/3)πr2h = (4 x 10/3 x 10/3 x 10/3) / (5x5x12) = 40 / 81 Volume of the sphere : Volume of the cone= 40 : 81
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