Question

A sphere of 4 cm radius is suspended within a hollow sphere of 6 cm radius. The inner sphere is charged to potential 3 e.s.u. and the outer sphere is earthed. The charge on the inner sphere is

Answer 1

Explanation:

Given a metal sphere of radius 4 cm is suspended within a hollow sphere of radius 6 centimeter. we have to determine charge on linear surface potential of inner surface is zero.

let charge on inner sphear is + q.

then; - Q charge is induced in the surface of outer sphere.

Now potential on inner sphere.=4πε01(r1q1+r2q2)

hance,Q1=charg on inner sphear

Given a metal sphere of radius 4 cm is suspended within a hollow sphere of radius 6 centimeter. we have to determine charge on linear surface potential of inner surface is zero.

let charge on inner sphere is + q.

then; - Q charge is induced in the surface of outer sphere.

Now potential on inner sphere.=4πε01(r1q1+r2q2)

hence,Q1=charge on inner sphere

r1=radius of inner sphere

q2&r2 is charge & radios of outer shell respectively.

given potential on inner sphear =3esu

r1=4cm

r2=6cm

∴3=4πε01[