Question

A sphere of aluminium of mass 50g is placed in boiling water for a long time. It is then immediately to 150g of water contained in a copper calorimeter of mass 100g at 20°C. The equilibrium temperature is found to be 25°C. Calculate the specific heat capacity of aluminium. Given specific heat of water and copper are 4200JKg^-1K^-1 and 385Kg^-1K-1.​

Answer 1

Answer:

he will come tell what kind of clause it was

Answer 2

Answer:

Heat given by water to reach 5

o

C+ Heat given by copper vessel to reach 5

o

C= Heat taken by ice to melt at 0

o

C+ Heat taken by melted ice to reach 5

o

C

m

w

c

w

Δt+m

c

c

c

Δt=m

i

L+m

i

c

w

δt

where Δt= change in temperature of water and copper vessel

m

w

= mass of water = 150g

m

c

= mass of copper vessel = 100g

m

i

= mass of ice

c

c

= specific heat capacity of copper

c

w

= specific heat capacity of water

L = specific latent heat of fusion of ice

δt = change in temperature of ice

Therefore, [150×4.2×(50−5)]+[100×0.4×(50−5)]=(m×336)+[m×4.2×(5−0)]

(150×4.2×45)+(100×0.4×45)=(m×336)+(m×4.2×m)

28350+1800=336m+21m

357m=30150

m=

357

30150

=84.45g of ice