A sphere of diameter 12 cm is dropped in a right circular cylinder vessel partly filled with water. If the sphere is completely submerged in water, the water level in the cylindrical vessel rises by 32/9cm. find the diameter of the cylindrical vessel.
Answers
Answered by
11
i am not sure whether it is right well
volume of sphere = volume of water risen
4/3*22/7*6*6*6 = 905.14
22/7*r^2*32/9 = 905.14
r^2 = (905.14*7*9)/22*32
= 82943.73
r = 287.99
d = 575.98
hence the answer
hope it is right!!
volume of sphere = volume of water risen
4/3*22/7*6*6*6 = 905.14
22/7*r^2*32/9 = 905.14
r^2 = (905.14*7*9)/22*32
= 82943.73
r = 287.99
d = 575.98
hence the answer
hope it is right!!
Similar questions