Question

A sphere of diameter 6 cm is dropped in a right
circular cylindrical vessel partly filled with water. The
diameter of the cylindrical vessel is 12 cm. If the sphere
is completely submerged in water, by how much will
the level of water rise in the cylindrical vessel ?

Answer 1

Answer:

1) diameter of the sphere ( d ) = 6cm

     radius of the sphere ( r ) = d/2 = 6/2 = 3cm

2 ) diameter of the cylindrical vessel ( D ) = 12 cm

radius of the cylindrical vessel ( R ) = 12/2 = 6 cm

level of water raised = h cm

according to the problem given ,

volume of the water raised in the vessel = volume of the sphere

πR²h = 4/3 × πr³

h = ( 4 × r³ ) / ( 3 × R² )

h = ( 4 × 3 × 3 × 3 ) / ( 3 × 6 × 6 )

h = 1 cm

Therefore ,

level of water raised in the vessel = h = 1 cm

I hope this helps you.

pls mark it as Brainliest...

Answer 2

Step-by-step explanation:

1 ) diameter of the sphere ( d ) = 6cm

     radius of the sphere ( r ) = d/2 = 6/2 = 3cm

2 ) diameter of the cylindrical vessel ( D ) = 12 cm

radius of the cylindrical vessel ( R ) = 12/2 = 6 cm

level of water raised = h cm

according to the problem given ,

volume of the water raised in the vessel = volume of the sphere

πR²h = 4/3 × πr³

h = ( 4 × r³ ) / ( 3 × R² )

h = ( 4 × 3 × 3 × 3 ) / ( 3 × 6 × 6 )

h = 1 cm

Therefore ,

level of water raised in the vessel = h = 1 cm