A sphere of diameter 6 cm is dropped into a cylindrical vessel partly filled with water. The radius of the vessel is 6 cm. If the sphere is completely submerged in water, find by how much the surface level of water will be raised.
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1 ) diameter of the sphere ( d ) = 6cm
radius of the sphere ( r ) = d/2 = 6/2 = 3cm
2 ) diameter of the cylindrical vessel ( D ) = 12 cm
radius of the cylindrical vessel ( R ) = 12/2 = 6 cm
level of water raised = h cm
according to the problem given ,
volume of the water raised in the vessel = volume of the sphere
πR²h = 4/3 × πr³
h = ( 4 × r³ ) / ( 3 × R² )
h = ( 4 × 3 × 3 × 3 ) / ( 3 × 6 × 6 )
h = 1 cm
Therefore ,
level of water raised in the vessel = h = 1 cm
this is your answer.....
radius of the sphere ( r ) = d/2 = 6/2 = 3cm
2 ) diameter of the cylindrical vessel ( D ) = 12 cm
radius of the cylindrical vessel ( R ) = 12/2 = 6 cm
level of water raised = h cm
according to the problem given ,
volume of the water raised in the vessel = volume of the sphere
πR²h = 4/3 × πr³
h = ( 4 × r³ ) / ( 3 × R² )
h = ( 4 × 3 × 3 × 3 ) / ( 3 × 6 × 6 )
h = 1 cm
Therefore ,
level of water raised in the vessel = h = 1 cm
this is your answer.....
mokalerishita9:
Thanks
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