a sphere of diameter 6cm is dropped in a right circular cylindrical vessel partly filled with water. the diameter of a cylindrical vessel is 12cm .of the sphere is completely submerged in water,by how much will the level of water rise in the cylindrical vessel..
Answers
★ A sphere of diameter 6cm is dropped in a right circular cylindrical vessel partly filled with water. the diameter of a cylindrical vessel is 12cm .of the sphere is completely submerged in water,by how much will the level of water rise in the cylindrical vessel. !?
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★ Diameter of the sphere ( d ) = 6cm
★ radius of the sphere ( r ) = d/2 = 6/2 = 3cm
★ Diameter of the cylindrical vessel ( D ) = 12 cm
★ radius of the cylindrical vessel ( R ) = 12/2 = 6 cm
★ level of water raised = h cm
according to the problem given ,
volume of the water raised in the vessel = volume of the sphere
πR²h = 4/3 × πr³
h = ( 4 × r³ ) / ( 3 × R² )
h = ( 4 × 3 × 3 × 3 ) / ( 3 × 6 × 6 )
h = 1 cm
Therefore , Level of water raised in the vessel = h = 1 cm .
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\huge\mathbb{\underline{QUESTION:-}}
★ A sphere of diameter 6cm is dropped in a right circular cylindrical vessel partly filled with water. the diameter of a cylindrical vessel is 12cm .of the sphere is completely submerged in water,by how much will the level of water rise in the cylindrical vessel. !?
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\huge\mathbb{\underline{SOLUTION:-}}
★ Diameter of the sphere ( d ) = 6cm
★ radius of the sphere ( r ) = d/2 = 6/2 = 3cm
★ Diameter of the cylindrical vessel ( D ) = 12 cm
★ radius of the cylindrical vessel ( R ) = 12/2 = 6 cm
★ level of water raised = h cm
according to the problem given ,
volume of the water raised in the vessel = volume of the sphere
πR²h = 4/3 × πr³
h = ( 4 × r³ ) / ( 3 × R² )
h = ( 4 × 3 × 3 × 3 ) / ( 3 × 6 × 6 )
h = 1 cm
Therefore , Level of water raised in the vessel = h = 1 cm .
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