A sphere of diameter 6cm is dropped in a right circular cylindrical vessel partly filled with water. The diameter of the cylindrical vessel is 12 cm. If the sphere is completely submerged in water, by how much will the level of water rise in the cylindrical vessel?
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Answer:
1 ) diameter of the sphere ( d ) = 6cm
radius of the sphere ( r ) = d/2 = 6/2 = 3cm
2 ) diameter of the cylindrical vessel ( D ) = 12 cm
radius of the cylindrical vessel ( R ) = 12/2 = 6 cm
level of water raised = h cm
according to the problem given ,
volume of the water raised in the vessel = volume of the sphere
πR²h = 4/3 × πr³
h = ( 4 × r³ ) / ( 3 × R² )
h = ( 4 × 3 × 3 × 3 ) / ( 3 × 6 × 6 )
h = 1 cm
Therefore ,
level of water raised in the vessel = h = 1 cm
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