Question

A sphere of diameter 7 cm and mass 266.5 gm floats in a bath of liquid

Answer 1

Hey dear,

◆ Answer-
γ = 7.48×10^-4 /°C

◆ Explanation-
# Given-
r = 7/2 = 3.5 cm
m = 266.5 g
ρ0 = 1.527 g/cm^3
∆T = 35 °C

# Solution-
Density of liquid at temp. 35 °C is-
density = mass / volume
ρ = m / (4πr^3/3)

Substituting values-
ρ = 266.5 / (1.33×3.142×3.5^3)
ρ = 1.487 g/cm^3

Coefficient of cubical expansion is given by-
γ = (ρ0-ρ) / (ρ0∆T)
γ = (1.527-1.487) / (1.527×35)
γ = 7.48×10^-4 /°C

Therefore, coefficient of cubical expansion of given liquid is 7.48×10^-4 /°C.

Hope this helps you...