A sphere of diameter 7 cm is dropped in a right circular cylinder vessel partly filled with water . the diameter of the cylindrical vessel is 14 cm if the sphere is completely submerged in water by how much will the level of water rise in the cylindrical vessel?
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Hello Mate!
So, we know that volume of water displaced is equal to the volume of sphere.
Volume of sphere, 4/3 πr³
= 4/3 × 22/7 × (7/2)³
= 4/3 × 22/7 × 7/2 × 7/2 × 7/2
= 179.7 cm³
volume of sphere = volume of water displaced
179.7 cm³ = πr²h
179.7 cm³ = 22/7 × 7² × h
179.7 cm³ = 22 × 7 × h
1.2 cm = height.
=> Hence water level will rise 1.2 cm.
Have great future ahead!
So, we know that volume of water displaced is equal to the volume of sphere.
Volume of sphere, 4/3 πr³
= 4/3 × 22/7 × (7/2)³
= 4/3 × 22/7 × 7/2 × 7/2 × 7/2
= 179.7 cm³
volume of sphere = volume of water displaced
179.7 cm³ = πr²h
179.7 cm³ = 22/7 × 7² × h
179.7 cm³ = 22 × 7 × h
1.2 cm = height.
=> Hence water level will rise 1.2 cm.
Have great future ahead!
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