Question

A sphere of lead of mass 10 g has net charge -2.5×10^(-9) C
i) What is the number of excess electrons on the sphere?
ii) How many excess electrons are per lead atom? Atomic number of lead is 82 and its atomic mass is 207 g/mol.

Answer 1

Answer:

Charrge = n* e -3*10^-9

hope this helps a bit