a sphere of m mass moving with a constant velocity hits another stationary sphere of the same mass. if e is the coefficient of restitution, then ratio of speed of first sphere to the speed of the second sphere after collision wiil be
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As no external force is not acting during the collision,we can apply,law of conservation of momentum.
Let,the 1st ball will move with a velocity of v and the 2nd one with x after the collision.
so, mu+m⋅0=m⋅v+m⋅x
or, v+x=u ...1
Now,coefficient of restitution in this case = x−vu−0=e (coefficient of restitution is defined as the ratio of relative velocity after the collision to relative veocity before the collision)
o, x−v=eu .... 2
solving, 1 & 2 we get,
x=u(e+1)2 and , v=u(1−e)2
So, v:x=(1−e):(1+e)
Let,the 1st ball will move with a velocity of v and the 2nd one with x after the collision.
so, mu+m⋅0=m⋅v+m⋅x
or, v+x=u ...1
Now,coefficient of restitution in this case = x−vu−0=e (coefficient of restitution is defined as the ratio of relative velocity after the collision to relative veocity before the collision)
o, x−v=eu .... 2
solving, 1 & 2 we get,
x=u(e+1)2 and , v=u(1−e)2
So, v:x=(1−e):(1+e)
rutu53:
please make my answer blainlist
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