Question

A sphere of mass 1/√3 kg is placed on two inclined planes of angle 30° and 60° with horizontal, as
shown. The normal reaction at point P (in N) is

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Answer 1

Answer:

answer is 5newton.

Explanation:

by resolving weight

Answer 2

Answer:

The normal reaction at P is $\frac{1}{3}$ N

Explanation:

By looking at the figure we can resolve the normal reaction in X and Y directions respectively.

By resolving components of normal reaction in X direction we get :
$M cos30^{0} = N cos60^0\\N\sqrt{3} = M$------ Eq - 1
By resolving components of normal reaction in Y direction we get :

$N sin 60^0 + M sin 30^0 = \frac{1}{\sqrt{3} }$ = W
Here W is the weight $\frac{1}{\sqrt3}$ Kg  and by using Eq - 1 we know
$N\sqrt{3} = M\\ N\frac{\sqrt{3}}{2} + N\frac{\sqrt{3}}{2} = \frac{1}{\sqrt{3}}$
On solving this we get N = $\frac{1}{3}$

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