A sphere of mass 10 kg and radius 0.5 m rotates about a tangent. The moment of inertia of the sphere is
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Answered by
14
Hi..
I=MR^2.
I=10×(0.5)^2
I=10×0.25
Thus I=2.5kg-m^2..
Hope this helps u!
I=MR^2.
I=10×(0.5)^2
I=10×0.25
Thus I=2.5kg-m^2..
Hope this helps u!
Rosedowson:
Pls mark d brainliest!
Answered by
26
here is your answer
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