Question

a sphere of mass 2 kg is dropped from a height of 0.4m onto a spring having force constant 1960n/m then maximum compression of spring will be

Answer 1

use work energy theoram here.

here When sphere dropped on spring will compress spring
and the energy store in form of potential energy..

so use this equation-
$mgh = \frac{1}{2} k {x}^{2}$
put
m=2,h=0.4,g=10 and k=spring constant

x will show maximum compression.

Answer 2

Hey dear here your
answer :::

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Initial PE of the block is = mgh = (2)(10)(0.4) = 8 J  [g = 10 m/s2]

When it hits the spring the compression of the spring is such that the mechanical energy of the block is equal to the potential energy stored in the spring.

So, ½ kx2 = 8

=> x2 = (2)(8)/(1960) = 0.008

=> x = 0.09 m = 9 cm

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Good Day :::