Question

A sphere of mass 2kg strikes another sphere of mass
3kg at rest with a velocity c 5 ms. If they move to
together after collision, then common velocity is
a) 1 ms.
b) 2 ms?
d) zero
c) 4 ms
( pls solve and give the appropriate solution)

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Answer 1

${ \huge \bf { \mid{ \overline{ \underline{Question}}} \mid}}$

A sphere of mass 2kg strikes another sphere of mass 3kg at rest with a velocity 5 m/s. If they move together after collision, then common velocity is?

$\huge{\bold{\underline{\underline{....Answer....}}}}$

$\huge{\bold{\underline{Given:-}}}$

• Mass of First Sphere (m) = 2 Kg.
• Velocity of First Sphere (u) = 5 m/s.
• Mass of Second sphere (M) = 3 Kg.
• Velocity of Second sphere (v) = 0 m/s.
• Velocity of Combined Sphere = ${\tt V_{final}}$

$\huge{\bold{\underline{Explanation:-}}}$

$\rule{300}{1.5}$

From Law of Conservation of momentum,

Initial Momentum = Final Momentum.

$\large{\boxed{\tt P_i = P_f}}$

$\large{\tt \leadsto mu + Mv = V_{final}(m + M)}$

(As both after the collision will move with same Velocity. )

Substituting the values ,

$\large{\tt \leadsto 2 \times 5 + 3 \times 0 = V_{final} \times (2 + 3)}$

$\large{\tt \leadsto 10 + 0 = V_{final} \times 5}$

$\large{\tt \leadsto 10 = V_{final} \times 5}$

$\large{\tt \leadsto V_{final} = \dfrac{10}{5}}$

$\large{\tt \leadsto V_{final} = \cancel{\dfrac{10}{5}}}$

Simplifying gives,

$\huge{\boxed{\boxed{\tt V_{final} = 2 \: m/s}}}$

So, the Common velocity of the Both the Body is 2 m/s (Option - b).

$\rule{300}{1.5}$

Answer 2

Answer:

Explanation

M1 = 2kg , m2 = 3kg , u1 = 5m/s , u2 = 0m/s , vf = ? ..

law of coservation of momemtum

pi=pf

m1u1+m2u2=vf[m1+m2]

2.5+3.0=vf[2+3]

10=vf(5)

vf=10/5

vf=2m/s.....

thank you ,hope it helps you