A sphere of mass 40 kg is alternated by another sphere
of mass 15 kg with a force of 1. mg-wt. Find the value
of G if the separation between the spheres is 20 cm.
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Answer:Distance (G)=20cm=0.2m
Mass (M
1
)=40kg Mass (m
2
)=15kg
Force (F)=0.1 milligram wt
=0.1×10
−3
×980 dyne
=98×10
−3
dyne
=98×10
−8
N
=9.8×10
−9
N
F=
R
2
GM
1
M
2
G=
M
1
M
2
Fk
2
=
40×15
9.8×10
−7
×0.2×0.2
=
4×15
98×2×2
×
10×10×10×10
10
−7
=6.5×10
−11
m
2
/kss
2
Explanation:
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