Question

A sphere of mass 40 kg is attracted by a second sphere of mass 60 kg with a force equal to 4 × 10^-5 N. If G= 6 × 10^-11 Nm²/kg². Calculate the distance between the two spheres.​

Answer 1

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⏩Here,

* m1= 40 kg,

* m2= 60 kg,

*F= 4 × 10^-5 N,

*G= 6 × 10^-11 Nm²/kg².

Now, as

$f = \: </em><em>G</em><em>\ \frac{m1m2}{r^{2} }$

Therefore,

$r = \: \sqrt{ \frac{</em><em>G</em><em>m1m2}{f} }$

$= > r = \sqrt{ \frac{6 \times 10 ^{ - 11} \times 40 \times 60}{ 4 \times 10^{ - 5} } }$

$= > r = \sqrt{36 \times 10 ^{ - 4} }$

$= > r = 6 \times 10^{ - 2} m$

or

r= 6 × 10^-2 × 100 = 6 cm. [The distance between the two spheres]

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Answer 2

Explanation:

Here,

* m1= 40 kg,

* m2= 60 kg,

*F= 4 × 10^-5 N,

*G= 6 × 10^-11 Nm²/kg².

Now, as

f = \: G\ \frac{m1m2}{r^{2} }f=G

r

2

m1m2

Therefore,

r= 6 × 10^-2 × 100 = 6 cm. [The distance between the two spheres]