A sphere of mass 40 kg is attracted by a second sphere of mass 80 kg with a
gravitational force equal to 13.34 × 10-11 N. If G=6.67 x 10-11 Nm2
/kg2
, calculate distance
between them.
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Step-by-step explanation:
Given A sphere of mass 40 kg is attracted by a second sphere of mass 80 kg with a gravitational force equal to 13.34 × 10-11 N. If G=6.67 x 10-11 Nm2 /kg2 calculate distance between them.
- So we have
- F = 13.34 x 10^-11
- G = 6.67 x 10^-11 N m^2 / kg^2
- m1 = 40 kg
- m2 = 80 kg
- Force F = Gm1m2 / r^2
- r = √Gm1m2 / F
- = √6.67 x 10^-11 x 40 x 80 / 13.34 x 10^-11
- = √ 1600
- r = 40 m
- r = 40 x 10^2 cm
Reference link will be
https://brainly.in/question/1645137
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