Question

A sphere of mass 40 kg is attracted by a second sphere of mass 80 kg with a

gravitational force equal to 13.34 × 10-11 N. If G=6.67 x 10-11 Nm2

/kg2

, calculate distance

between them.​

Answer 1

Bodies are separated by 40 metres.

Given:

• 40 kg attracts 80 kg mass with a force of 13.34 × 10^(-11) Nm².

To find:

Distance between the bodies?

Calculation:

According to Gravitational Law,

$F = \dfrac{G(m1)(m2)}{ {d}^{2} }$

• G is Universal Gravitational Constant and 'd' is separation distance

$\implies {d}^{2} = \dfrac{G(m1)(m2)}{ F}$

$\implies {d}^{2} = \dfrac{6.67 \times {10}^{ - 11} (40)(80)}{ 13.34 \times {10}^{ - 11} }$

$\implies {d}^{2} = \dfrac{3200}{ 2 }$

$\implies {d}^{2} = 1600$

$\implies \: d = \sqrt{1600}$

$\implies \: d = 40 \: m$

So, the separation distance is 40 metres.