Question

A sphere of mass 40 kg is attracted by another sphere of mass 80kg by a force of 2.5 multiplied by 10 raised to the power minus 6 newton when their centres are apart from 30 mm . Find the value of G

Answer 1

Answer:

We know that gravitational force between two bodies is given by

F = Gm1m2/r2

Where m1,m2 are masses of the bodies G is universal gravitation constant. r is the distance between two objects from their centers.

So, here

F = 2.5×10 to the power minus 6

r = 30mm or 30×10 to the power minus 3

m1 = 40kg

m2 = 80kg

we have to find the value of G

So F = Gm1m2/r2

2.5×10to the power -6 = G×40×80/3×10to the power -2

So, we get G = 0.0023×10 to the power minus 8

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