a sphere of mass 40 kg is attracted by another sphere of mass 80kg by a force of
2.5 x 10 ^-6 N when the centres are 3x10^-2 m apart
find the value of G
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GIVEN:
- Mass of the first sphere (m₁) = 40 Kg.
- Mass of the second sphere (m₂) = 80 Kg.
- Force (F) = 2.5 x 10⁻⁶ N.
- Distance between the spheres (d) = 3x10⁻² m.
TO FIND:
- Value of G.
SOLUTION:
Use this formula:
Where:
- F is force.
- m₁ and m₂ are mass of the objects.
- d is distance.
- G is universal gravitation constant.
Substitute.
▣ Use the radicle rule : (a×b)ⁿ=aⁿ×bⁿ to simplify the denominator.
▣ Use the radicle rule = (mᵃ)ᵇ=mᵃᵇ. Moreover, 3²=9 and 40×80 = 3200.
▣ Now transpose.
G is 7.03×10⁻¹³ N·m²/kg².
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