Question

a sphere of mass 40 kg is attracted by another sphere of mass 80 kg by a force when their centres 300 CM apart find the value of if g is equal to 6.67 into 10 ki power minus 11 Newton metre square per floor of square​

Answer 1

We know,

F = G(m1m2) ÷ r²

F = (6.67×10^-11)(40×80) ÷ 3×3

F = (6.67×10^-11)(3200) ÷ 9

F = 2.37×10^-8 N