Question

a sphere of mass 40 kg is being attracted by another sphere of mass 15 kg when they are 0.2 CM apart with the force of 9.8 x 10 -N and calculate the value of G ​

Answer 1

Answer: Distance(r)= 0.2 cm= 0.002m

m1= 40kg , m2= 15kg

F= 9.8×10^-7 N

G= F×r^2/ m1×m2

G= 9.8×10^-7 × 0.002×0.002 / 40×15

G= 9.8×10^-7 × 4× 10^-6 / 40×15

G= 0.6533× 10^-12

G= 6.533×10^-13

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